0.0855t^2-0.914t+1.703=0

Solution for 0.0855t^2-0.914t+1.703=0 equation:

0.0855t^2-0.914t+1.703=0

a = 0.0855; b = -0.914; c = +1.703;
Δ = b2-4ac
Δ = -0.9142-4·0.0855·1.703
Δ = 0.25297
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.914)-\sqrt{0.25297}}{2*0.0855}=\frac{0.914-\sqrt{0.25297}}{0.171}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.914)+\sqrt{0.25297}}{2*0.0855}=\frac{0.914+\sqrt{0.25297}}{0.171}
$